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3) The solubility of a gas in water is 0.22 g/L at 20.0 kPa of pressure. What is the solubility when the pressure is increased t
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Answers ( )
Answer:
1.27g/L is the new solubility when the pressure is increased
Explanation:
Based on Henry’s law, the solubility of a gas is directly proportional to the partial pressure of the gas in equilibrium.
The equation is:
S1 / P1 = S2 / P2
Where S is solubility and P the pressure of 1, initial state and 2, final state.
The values of the problem are:
S1 = 0.22g/L
P1 = 20.0kPa
S2 = 115kPa
P2 = ?
0.22g/L / 20.0kPa = S2 / 115kPa
S2 = 0.22g/L* 115kPa / 20.0kPa
S2 = 1.27g/L is the new solubility when the pressure is increased