3) The solubility of a gas in water is 0.22 g/L at 20.0 kPa of pressure. What is the solubility when the pressure is increased t

Question

3) The solubility of a gas in water is 0.22 g/L at 20.0 kPa of pressure. What is the solubility when the

pressure is increased to 115 kPa?

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Farah 3 years 2021-09-02T12:14:08+00:00 1 Answers 57 views 0

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    2021-09-02T12:15:18+00:00

    Answer:

    1.27g/L is the new solubility when the pressure is increased

    Explanation:

    Based on Henry’s law, the solubility of a gas is directly proportional to the partial pressure of the gas in equilibrium.

    The equation is:

    S1 / P1 = S2 / P2

    Where S is solubility and P the pressure of 1, initial state and 2, final state.

    The values of the problem are:

    S1 = 0.22g/L

    P1 = 20.0kPa

    S2 = 115kPa

    P2 = ?

    0.22g/L / 20.0kPa = S2 / 115kPa

    S2 = 0.22g/L* 115kPa  / 20.0kPa

    S2 = 1.27g/L is the new solubility when the pressure is increased

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )