3. An iron cube (p = 7860 kg/m?) having sides of 1 cm is submerged in open fresh water (p = 1000 kg/m?) with its top surface at a depth

Question

3. An iron cube (p = 7860 kg/m?) having sides of 1 cm is submerged in open fresh water (p = 1000
kg/m?) with its top surface at a depth of 2.5 m. Considering that its top surface is held horizontal
with respect to the water surface, determine the difference in pressure between the top and
bottom surfaces of the cube?​

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Trung Dũng 3 years 2021-07-14T01:16:32+00:00 1 Answers 5 views 0

Answers ( )

  1. thnahdat
    0
    2021-07-14T01:18:11+00:00
    Reply

    Answer:

    \Delta P = 98.07\,Pa

    Explanation:

    The difference in pressure between the top and bottom surfaces is determined by the following hydrostatic expression:

    \Delta P = \rho_{w}\cdot g \cdot \Delta z

    \Delta P = \left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.01\,m)

    \Delta P = 98.07\,Pa

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