3.7.6. A satellite is in a circular orbit around the Earth. If it is at an altitude equal to twice the radius of the Earth, 2RE, how does it

Question

3.7.6. A satellite is in a circular orbit around the Earth. If it is at an altitude equal to twice the radius of the Earth, 2RE, how does its speed v relate to the Earth’s radius RE, and the magnitude g of the acceleration due to gravity on the Earth’s surface?a)b)c)d)e)

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Delwyn 6 months 2021-07-18T23:13:10+00:00 1 Answers 40 views 0

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    2021-07-18T23:14:58+00:00

    Answer:

    Explanation:

    For acceleration due to gravity

    g = GM / R²  —————————- ( 1 )

    At height 2R , radius of orbit is 3R .

    If speed of satellite be v

    m v² / 3R = GMm / (3R)² ( centripetal force = gravitational force )

    v² = GM / 3R ————————————– ( 2 )

    Dividing (1) and (2)

    v² / g = R / 3

    v² = gR / 3

    v = √( gR / 3 )

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