2A + N2 -> 2AIN How many moles of aluminum nitride form when 5.00 g of aluminum reacts with excess nitrogen? K 0.0925 mol 0 0.185 mol Ole

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2A + N2 -> 2AIN How many moles of aluminum nitride form when 5.00 g of aluminum reacts with excess nitrogen? K 0.0925 mol 0 0.185 mol Oleo mol z se mol​

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Vodka 5 years 2021-08-29T04:29:07+00:00 1 Answers 57 views 0

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  1. Thunguyet
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    2021-08-29T04:30:45+00:00
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    Answer:

    0.185 moles of AlN

    Explanation:

    The equation is:

    2Al  +  N₂  →  2AlN

    This reaction indicates that 2 mol of aluminum can react to 1 mol of nitrogen to produce 2 moles of aluminum nitride.

    We convert the aluminum’s mass to moles

    5 g/ 26.98 g/mol = 0.185 moles.

    2 moles of Al are needed to produce 2 moles of AlN

    so, ratio is 1:1

    In conclussion we say:

    0.185 moles of Al, must produce 0.185 moles of AlN

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )