20 points and brainliest‼️‼️‼️‼️ A 4.88 x 10-6 C charge moves 265 m/s parallel (at 0°) to a magnetic field of 0.0579 T. Wh

Question

20 points and brainliest‼️‼️‼️‼️
A 4.88 x 10-6 C charge moves 265 m/s
parallel (at 0°) to a magnetic field of
0.0579 T. What is the magnetic force
on the charge?

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Khải Quang 5 years 2021-07-26T02:36:18+00:00 1 Answers 10 views 0

Answers ( )

  1. kiet
    0
    2021-07-26T02:38:06+00:00
    Reply

    Answer:

    0 N

    Explanation:

    Applying,

    F = qvBsin∅…………….. Equation 1

    Where F = Force on the charge, q = charge, v = Velocity, B = magnetic charge, ∅ = angle between the velocity and the magnetic field.

    From the question,

    Given: q = 4.88×10⁻⁶ C, v = 265 m/s, B = 0.0579 T, ∅ = 0°

    Substitute these values into equation 1

    F = ( 4.88×10⁻⁶)(265)(0.0579)(sin0)

    Since sin0° = 0,

    Therefore,

    F = 0 N

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