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2 resistors of resistance 1000 ohm and 2000 ohm are joined in series with a 100V supply. A voltmeter of internal resistance 4000 ohm is conn
Question
2 resistors of resistance 1000 ohm and 2000 ohm are joined in series with a 100V supply. A voltmeter of internal resistance 4000 ohm is connected to measure the potential difference across 1000 ohm resistor. Calculate the reading shown by the voltmeter.
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Physics
3 years
2021-08-20T21:51:48+00:00
2021-08-20T21:51:48+00:00 1 Answers
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Answers ( )
The voltmeter reading will be 35.7 volt
Explanation:
The resistor 1000 ohm and 4000 ohm are connected in parallel .
Their combined resistance is supposed R₁
Thus = +
or R₁ = 800 ohm
Therefore the total resistance in circuit is = 2000 + 800 = 2800 ohm
Because these are in series .
We can find current flowing through the circuit I = = =
here R is total resistance .
The potential difference across 1000 ohm = x 1000 = 35.7 volt
Thus voltmeter reading will be 35.7 volt