2. A 0.02 kg ball spins in a horizontal circle of radius 0.50 m with a frequency of 4.0 Hz. What is the tension force in the string (t

Question

2. A 0.02 kg ball spins in a horizontal circle of radius 0.50 m with a frequency
of 4.0 Hz. What is the tension force in the string (the centripetal force on
the ball)?

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Cherry 5 years 2021-08-26T03:00:10+00:00 1 Answers 66 views 0

Answers ( )

  1. Nem
    0
    2021-08-26T03:01:42+00:00
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    Answer:

    T = 6.3 N

    Explanation:

    ω = 2πf = 2π(4.0) = 8π rad/s

    T = mω²R = 0.02(8π)²(0.50) = 6.31654…

    If the ball is supported only by the string, there is also a vertical force of

    0.02(9.8) = 0.196 N, but it is so small compared to the horizontal force  that vectoral addition will not change the result.

    T = √(6.31654² + 0.196²) = 6.31958

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