16) Consider the equation: gx – hx = j g = h, j = 0 and g, h, and j are non- negative integers, then the equation has how

Question

16) Consider the equation: gx – hx = j
g = h, j = 0 and g, h, and j are non-
negative integers, then the equation has
how many solutions?

in progress 0
Thiên Thanh 3 years 2021-07-23T15:35:25+00:00 1 Answers 16 views 0

Answers ( )

    0
    2021-07-23T15:36:59+00:00

    Step-by-step explanation:

    where p is a positive prime number.

    2. Preliminaries

    The Catalan’s conjecture is a well known conjecture. This conjecture states

    that (3, 2, 2, 3) is a unique solution (a, b, x, y) for the Diophantine equation

    a

    x − b

    y = 1 where a, b, x and y are integers with min{a, b, x, y} > 1. In 2004,

    this conjecture was proven in 2004 by Mihailescu [3].

    Proposition 2.1. [3] (3, 2, 2, 3) is a unique solution (a, b, x, y) for

    the Diophantine equation a

    x − b

    y = 1 where a, b, x and y are integers with

    min{a, b, x, y} > 1.

    Next, we will prove two Lemmas by Proposition 2.1.

    Lemma 2.2. (1, 3) is a unique solution (x, z) for the Diophantine equation

    8

    x + 1 = z

    2 where x and z are non-negative integers.

    Proof. Let x, y and z be non-negative integers such that 8x + 1 = z

    2

    . If

    x = 0, then z

    2 = 2 which is impossible. Then x ≥ 1. Thus, z

    2 = 8x + 1 ≥

    8

    1 + 1 = 9. Then z ≥ 3. Now, we consider on the equation z

    2 − 8

    x = 1. By

    Proposition 2.1, we have x = 1. Then z = 3. Hence, (1, 3) is a unique solution

    (x, z) for the equation 8x + 1 = z

    2 where x and z are non-negative integers.

    Lemma 2.3. The Diophantine equation 1 + 19y = z

    2 has no non-negative

    integer solution.

    Proof. Suppose that there are non-negative integers y and z such that 1 +

    19y = z

    2

    . If y = 0, then z

    2 = 2 which is impossible. Then y ≥ 1. Thus,

    z

    2 = 1 + 19y ≥ 1 + 191 = 20. Then z ≥ 5. Now, we consider on the equation

    z

    2 − 19y = 1. By Proposition 2.1, we have y = 1. Then z

    2 = 20. This is a

    contradiction. Hence, the equation 1 + 19y = z

    2 has no non-negative integer

    solution.

    3. Results

    In [4], the Diophantine equation 8x + 19y = z

    2 has no non-negative integer

    solution. But we will show in this section that (1, 0, 3) is a unique solution

    (x, y, z) for the Diophantine equation 8x + 19y = z

    2 where x, y and z are non

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )