15 J of work were expended moving an 18 kg block. At what velocity did the block move?

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15 J of work were expended moving an 18 kg block. At what velocity did the block move?

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Diễm Thu 5 months 2021-08-31T05:45:29+00:00 1 Answers 42 views 0

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    2021-08-31T05:46:52+00:00

    Answer:√(5/3)m/s

    Explanation:

    Kinetic energy(ke)=15j

    Mass(m)=18kg

    Velocity(v)=?

    Ke=(mxv^2)/2

    15=(18xv^2)/2

    Cross product

    (18xv^2)=15×2

    18xv^2=30

    Divide both sides by 18

    (18xv^2) ➗ 18=30 ➗ 18

    v^2=5/3

    v=√(5/3)

    v=√(5/3)m/s

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