Question in progress 0 Môn Toán Doris 6 years 2020-10-15T06:55:55+00:00 2020-10-15T06:55:55+00:00 1 Answers 98 views 0
Answers ( )
– Ta có: `HB = 25/13` và `HC = 144/13`
`⇒BC = HB + HC = 25/13 + 144/13 = 13`
– Xét `ΔABC` vuông tại `A`, đường cao `AH` có:
+ `AC^2 = CH * BC = 144/13*13 = 144`
`⇒AC = \sqrt{144} = 12`
+ `AB^2 = BH * BC = 25/13*13 = 25`
`⇒AB = \sqrt{25} = 5`
Vậy `AB = 5`; `AC = 12`