1). What is the equation of the line that is perpendicular to y= -3x+1 that passes through the point (9,0)? 2). What is the equat

Question

1). What is the equation of the line that is perpendicular to y= -3x+1 that passes through the point (9,0)?

2). What is the equation of the line that is parallel to y= -3x+1 that passes through the point (9,0)?

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Thái Dương 3 years 2021-08-02T00:44:14+00:00 2 Answers 6 views 0

Answers ( )

    0
    2021-08-02T00:45:17+00:00

    Answer:

    Step-by-step explanation:

    1) Slope of the given line = -3

    slope of the perpendicular line = 1/3

    y – 0 = 1/3(x-9)

    y = 1/3x – 3

    2) slope of the parallel line = -3

    y – 0 = -3(x-9)

    y = -3x + 27

    0
    2021-08-02T00:45:49+00:00

    Answer:

    1). y = 1/3x – 3       2).y = -3x + 27

    Step-by-step explanation:

    1). y = 1/3x + b

    0 = 1/3(9) + b

    0 = 3 + b

    -3 = b

    y = 1/3x – 3

    2)/ y = -3x + b

    0 = -3(9) + b

    0 = -27 + b

    27 = b

    y = -3x + 27

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