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1). What is the equation of the line that is perpendicular to y= -3x+1 that passes through the point (9,0)? 2). What is the equat
Question
1). What is the equation of the line that is perpendicular to y= -3x+1 that passes through the point (9,0)?
2). What is the equation of the line that is parallel to y= -3x+1 that passes through the point (9,0)?
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Mathematics
3 years
2021-08-02T00:44:14+00:00
2021-08-02T00:44:14+00:00 2 Answers
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Answers ( )
Answer:
Step-by-step explanation:
1) Slope of the given line = -3
slope of the perpendicular line = 1/3
y – 0 = 1/3(x-9)
y = 1/3x – 3
2) slope of the parallel line = -3
y – 0 = -3(x-9)
y = -3x + 27
Answer:
1). y = 1/3x – 3 2).y = -3x + 27
Step-by-step explanation:
1). y = 1/3x + b
0 = 1/3(9) + b
0 = 3 + b
-3 = b
y = 1/3x – 3
2)/ y = -3x + b
0 = -3(9) + b
0 = -27 + b
27 = b
y = -3x + 27