1 Tìm x bt a x^2-2x+1=0 b 9-6x+x^2=0 c 25x^2-10x+1=10 d 49x^2-28x+4

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1 Tìm x bt a x^2-2x+1=0 b 9-6x+x^2=0 c 25x^2-10x+1=10 d 49x^2-28x+4

Question

1 Tìm x bt
a x^2-2x+1=0
b 9-6x+x^2=0
c 25x^2-10x+1=10
d 49x^2-28x+4

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Môn Toán Delwyn 4 years 2020-10-14T03:41:40+00:00 2020-10-14T03:41:40+00:00 1 Answers 125 views 0

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Captcha* Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )

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minhkhoi · Answer 1 · 2020-10-14T03:43:25+00:00

minhkhoi

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2020-10-14T03:43:25+00:00 October 14, 2020 at 3:43 am

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$a) x^{2} - 2 x + 1 = 0$

$\Leftrightarrow (x - 1)^{2} = 0$

$\Leftrightarrow x - 1 = 0$

$\Leftrightarrow x = 1$

$Vậy x = 1$

$b) 9 - 6 x + x^{2} = 0$

$\Leftrightarrow (3 - x)^{2} = 0$

$\Leftrightarrow 3 - x = 0$

$\Leftrightarrow x = 3$

$Vậy x = 3$

$c) 25 x^{2} - 10 x + 1 = 0$

$\Leftrightarrow (5 x - 1)^{2} = 0$

$\Leftrightarrow 5 x - 1 = 0$

$\Leftrightarrow 5 x = 1$

$\Leftrightarrow x = \frac{1}{5}$

$Vậy x = \frac{1}{5}$

$d) 49 x^{2} - 28 x + 4 = 0$

$\Leftrightarrow (7 x - 2)^{2} = 0$

$\Leftrightarrow 7 x - 2 = 0$

$\Leftrightarrow 7 x = 2$

$\Leftrightarrow x = \frac{2}{7}$

$Vậy x = \frac{2}{7}$

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