1. The uniform purely axial magnetic induction required by the experiment in a volume large enough to accommodate the Lorentz Tube is produc

Question

1. The uniform purely axial magnetic induction required by the experiment in a volume large enough to accommodate the Lorentz Tube is produced by the Helmholtz Coils. What is the magnetic induction due to a coil current 1.5 Ampere

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Thu Nguyệt 3 years 2021-08-17T11:32:55+00:00 1 Answers 8 views 0

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    2021-08-17T11:34:30+00:00

    Complete Question

    The uniform purely axial magnetic induction required by the experiment in a volume large enough to accommodate the Lorentz Tube is produced by the Helmholtz Coils. What is the magnetic induction due to a coil current 1.5 Ampere? Convert the result in the still popular non-SI unit Gauss (1 Tesla = 10^4 Gauss).

    B = N*mue*I/(2*r)

    # of loops = 140

    radius of the coil = 0.14m

    Answer:

     The magnetic induction is B  = 2.639 \  Gauss

    Explanation:

    From the question we are told that

         The coil current is  I  =  1.5 \ A

         The number of loops is  N  =  140

    The magnetic field due to the current is mathematically represented as

               B  =  \mu_o *  N  *  I

    \mu_o is the permeability of free space with value  \mu_o  =   4\pi * 10^{-7} N/A^2

    substituting value

               B  =   4\pi * 10^{-7}   * 140 * 1.5

               B  =  2.639*19^{-4} \ T

    From question

            (1 Tesla = 10^4 \ Gauss).

    =>      B  =  2.693 *10^{-4} *10^4 =  2.63 \ Gauss

    =>      B  = 2.639 \  Gauss

             

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