1. A drop of oil of volume 10-10 m spreads out on water to make a circular film of radius 10 m. what is the thickness of the film?

Question

1. A drop of oil of volume 10-10 m spreads out on water to
make a circular film of radius 10 m. what is the thickness
of the film?​

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Kim Cúc 5 years 2021-09-03T05:54:24+00:00 1 Answers 14 views 0

Answers ( )

  1. Dau
    0
    2021-09-03T05:55:41+00:00
    Reply

    Answer:

    318.3 nm

    Explanation:

    We approximate the circular film as a cylinder of height h and radius, r. Its volume V = πr²h. Since this volume equals the volume of the oil drop, the height of the circular film is thus h = V/πr²

    V = 10⁻¹⁰ m³ and r = 10 m

    Substituting into h, we have

    h = 10⁻¹⁰ m³/π(10)²

    = 0.3183 × 10⁻¹² m

    = 3183 × 10⁻⁹ m

    = 318.3 nm

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