1. A bag dropped from a helicopter falls with an acceleration of 9.8m/s2. What is its velocity after 5s?

Question

1. A bag dropped from a helicopter falls with an acceleration of 9.8m/s2. What is its velocity after 5s?

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Nem 4 years 2021-08-16T13:12:36+00:00 1 Answers 18 views 0

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  1. minhkhoi
    0
    2021-08-16T13:14:32+00:00
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    Answer:

    The answer is 49m/s.

    Explanation:

    Given,

    acceleration (a) =9.8m/s^2

    initial velocity (u)=0 (as it was in rest condition in helicopter)

    time (t) =5 s

    now, final velocity (v) after 5s =?

    we have,

    a = \frac{v - u}{t}

    or \: 9.8 = \frac{v - 0}{5}

    or, v = 49m/s

    Therefore, the velocity after 5s is 49m/s.

    Hope it helps..

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