problem A newly established colony on the Moon launches a capsule vertically with an initial speed of 1.445 km/s. Ignoring the rotation of t

Question

problem A newly established colony on the Moon launches a capsule vertically with an initial speed of 1.445 km/s. Ignoring the rotation of the Moon, what is the maximum height reached by the capsule

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Khải Quang 4 years 2021-09-02T07:59:58+00:00 2 Answers 51 views 0

Answers ( )

  1. danthu
    0
    2021-09-02T08:01:17+00:00
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    Answer:

    104.4km

    Explanation:

    Projectile motion occurs when object is launched into air and allowed to fall freely under the influence of gravity.

    Maximum height reached by the object is expressed as;

    H = u²sin²(theta)/2g where;

    u is the initial velocity = 1.445km/s

    u = 1445m/s since 1000m is equivalent to 1km

    theta is the angle of launch

    g is the acceleration due to gravity = 10m/s²

    theta = 90° (since object is launched vertically)

    Substituting the values in the formula we have;

    H = 1445²(sin90°)²/2(10)

    H = 1445²/20

    H = 104,401.25m

    H = 104.4km

    The the maximum height reached by the capsule is 104.4km

  2. mit
    0
    2021-09-02T08:01:44+00:00
    Reply

    Answer:

    Maximum height =1031km

    Explanation:

    Given:

    Velocity,Vo= 1.445km/s= 1445m/s

    Mass of moon= 7.35×10^22kg

    Radius of moon= 1737km= 1737000m

    Using conservation energy

    Ui + Ki= Uf + Kf

    –‘>(GMm/R) + 1/2 (m ^2)

    -GMm/(R + h) – 0

    Vo^2= 2Gm(1/R – 1/R+h)

    1445^2= 2× (6.67×10^-11)×(7.35×10^22)[(1/1737000)- (1/1737000 + h)]

    h= 1031km

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