problem A newly established colony on the Moon launches a capsule vertically with an initial speed of 1.445 km/s. Ignoring the rotation of the Moon, what is the maximum height reached by the capsule
Question
Question
problem A newly established colony on the Moon launches a capsule vertically with an initial speed of 1.445 km/s. Ignoring the rotation of the Moon, what is the maximum height reached by the capsule
Answer:
104.4km
Explanation:
Projectile motion occurs when object is launched into air and allowed to fall freely under the influence of gravity.
Maximum height reached by the object is expressed as;
H = u²sin²(theta)/2g where;
u is the initial velocity = 1.445km/s
u = 1445m/s since 1000m is equivalent to 1km
theta is the angle of launch
g is the acceleration due to gravity = 10m/s²
theta = 90° (since object is launched vertically)
Substituting the values in the formula we have;
H = 1445²(sin90°)²/2(10)
H = 1445²/20
H = 104,401.25m
H = 104.4km
The the maximum height reached by the capsule is 104.4km
Answer:
Maximum height =1031km
Explanation:
Given:
Velocity,Vo= 1.445km/s= 1445m/s
Mass of moon= 7.35×10^22kg
Radius of moon= 1737km= 1737000m
Using conservation energy
Ui + Ki= Uf + Kf
–‘>(GMm/R) + 1/2 (m ^2)
-GMm/(R + h) – 0
Vo^2= 2Gm(1/R – 1/R+h)
1445^2= 2× (6.67×10^-11)×(7.35×10^22)[(1/1737000)- (1/1737000 + h)]
h= 1031km