Potential difference of a battery is 2.2 V when it is connected across a resistance of 5 ohm, if suddenly the potential difference

Question

Potential difference of a battery is 2.2 V when it is connected
across a resistance of 5 ohm, if suddenly the potential difference
falls to 1.8V, its internal resistance will be​

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Jezebel 3 years 2021-08-23T08:45:31+00:00 1 Answers 165 views 0

Answers ( )

  1. Calantha
    0
    2021-08-23T08:46:54+00:00
    Reply

    Answer:

    1.1ohms

    Explanation:

    According to ohms law E = IR

    If potential difference of a battery is 2.2 V when it is connected across a resistance of 5 ohm and if suddenly the voltage Falls to 1.8V then the current in the 5ohms resistor I = V/R = 1.8/5

    I = 0.36A (This will be the load current).

    Before we can calculate the value of the internal resistance, we need to know the voltage drop across the internal resistance.

    Voltage drop = 2.2V – 1.8V = 0.4V

    Then we calculate the internal resistance using ohms law.

    According to the law, V = Ir

    V= voltage drop

    I is the load current

    r = internal resistance

    0.4 = 0.36r

    r = 0.4/0.36

    r = 1.1 ohms

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