Polygon A is similar to polygon B the sides of polygon A are three times larger then the corresponding sides of polygon B the perimeter of p

Question

Polygon A is similar to polygon B the sides of polygon A are three times larger then the corresponding sides of polygon B the perimeter of polygon A is 144 what is the perimeter of polygon B ?

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Thu Cúc 3 years 2021-08-08T13:09:12+00:00 2 Answers 14 views 0

Answers ( )

  1. kimchi2
    0
    2021-08-08T13:10:28+00:00
    Reply

    Answer:

    • 48 units

    Step-by-step explanation:

    Perimeter is the sum of the side lengths

    If polygon A has perimeter

    • P  = a+b+c+d for example

    Then polygon B has perimeter of

    • P’ = 1/3a+1/3b+1/3+1/3d = 1/3P as each side is 3 times smaller than the corresponding side

    Since P = 144

    • P’ = 1/3P = 1/3*144 = 48 units
  2. Amity
    0
    2021-08-08T13:10:40+00:00
    Reply

    We can write a ratio comparing the sides of both polygons.

    A:B = 3:1

    Since we know that 144 is the perimeter for polygon A, we can substitute it.

    144:B = 3:1

    ~Simplify

    144 = 3B

    Divide 3 to both sides

    48 = B

    Therefore, the perimeter of B is 48 units.

    Best of Luck!

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