PLEASE HELP !! When finding the margin of error for the mean of a normally distributed population from a sample, what is the critical probab

Question

PLEASE HELP !! When finding the margin of error for the mean of a normally distributed population from a sample, what is the critical probability, assuming a confidence level of 58%?
0.21
0.42
0.58
0.79

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Thái Dương 5 years 2021-07-30T03:54:22+00:00 2 Answers 112 views 0

Answers ( )

  1. mocmien2
    0
    2021-07-30T03:56:15+00:00
    Reply

    wouldn’t it be 0.58 because if you turn 58% into a decimal it will be 0.58.

  2. Farah
    0
    2021-07-30T03:56:21+00:00
    Reply

    Answer:

    D) 0.79

    Step-by-step explanation:

    First, find alpha.

    \alpha = 1 – (confidence level / 100)

    \alpha = 1 – \frac{58}{100}

    \alpha = 1 – 0.58

    \alpha = 0.42

    Then, you can solve for the critical probability.

    p* = 1 – \frac{\alpha}{2}

    p* = 1 – \frac{0.42}{2}

    p* = 1 – 0.21

    p* = 0.79

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