One number is six more than another number. The sum of their squares is 90.

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One number is six more than another number. The sum of their squares is 90.

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Đan Thu 3 years 2021-07-20T04:50:17+00:00 1 Answers 21 views 0

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    2021-07-20T04:51:55+00:00

    First number: x
    Second: x + 6
    (x)^2 + (x + 6)^2 = 90
    x^2 + x^2 + 6x + 6x + 36 = 90
    Simplify more
    2x^2 + 12x + 36 = 90
    2x^2 + 12x – 54 = 0
    2(x + 9)(x – 3) = 0
    You know that x = -9, and 3
    The first number is 3, the other -9

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