One number exceeds another number by 6. One fourth of the sum of the two numbers is two less than the smaller. Find the numbers.

Question

One number exceeds another number by 6. One fourth of the sum of the two numbers is two less than the smaller.
Find the numbers.

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Sapo 3 years 2021-08-03T11:24:18+00:00 1 Answers 22 views 0

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  1. Philomena
    0
    2021-08-03T11:25:26+00:00
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    Answer:

    7 and 13

    Step-by-step explanation:

    let the 2 numbers be x and y , x > y , then

    x = y + 6 → (1)

    \frac{1}{4} (x + y) = y – 2 ( multiply both sides by 4 to clear the fraction )

    x + y = 4y – 8 ( subtract 4y from both sides )

    x – 3y = – 8 → (2)

    Substitute x = y + 6 into (2)

    y + 6 – 3y = – 8

    – 2y + 6 = – 8 ( subtract 6 from both sides )

    – 2y = – 14 ( divide both sides by – 2 )

    y = 7

    Substitute y = 7 into (1)

    x = 7 + 6 = 13

    The 2 numbers are 7 and 13

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