Nitrogen at an initial state of 300 K, 150 kPa, and 0.2 m3is compressed slowly in an isothermal process to a final pressure of 800 kPa. Determine the work done during this process.
Nitrogen at an initial state of 300 K, 150 kPa, and 0.2 m3is compressed slowly in an isothermal process to a final pressure of 800 kPa. Determine the work done during this process.
Answer:
[tex]W=-251096.465\ J[/tex] negativesign denotes thatthe work is consumed by the system.
Explanation:
Given:
Isothermal process.
initial temperature, [tex]T_1=300\ K[/tex]
initial pressure, [tex]P_1=150kPa[/tex]
initial volume, [tex]V_1=0.2\ m^3[/tex]
final pressure, [tex]P_2=800\ kPa[/tex]
The work done during an isothermal process is given by:
[tex]W=P_1.V_1\times ln(\frac{P_1}{P_2} )[/tex]
[tex]W=150\times 1000\times \ln\frac{150}{800}[/tex]
[tex]W=-251096.465\ J[/tex] negativesign denotes thatthe work is consumed by the system.