Nitrogen at an initial state of 300 K, 150 kPa, and 0.2 m3is compressed slowly in an isothermal process to a final pressure of 800 kPa. Dete

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Nitrogen at an initial state of 300 K, 150 kPa, and 0.2 m3is compressed slowly in an isothermal process to a final pressure of 800 kPa. Determine the work done during this process.

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Khải Quang 3 years 2021-09-04T22:30:14+00:00 1 Answers 11 views 0

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  1. haidang
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    2021-09-04T22:31:55+00:00
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    Answer:

    W=-251096.465\ J negativesign denotes thatthe work is consumed by the system.

    Explanation:

    Given:

    Isothermal process.

    initial temperature, T_1=300\ K

    initial pressure, P_1=150kPa

    initial volume, V_1=0.2\ m^3

    final pressure, P_2=800\ kPa

    The work done during an isothermal process is given by:

    W=P_1.V_1\times ln(\frac{P_1}{P_2} )

    W=150\times 1000\times \ln\frac{150}{800}

    W=-251096.465\ J negativesign denotes thatthe work is consumed by the system.

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