Nitrogen at an initial state of 300 K, 150 kPa, and 0.2 m3is compressed slowly in an isothermal process to a final pressure of 800 kPa. Determine the work done during this process.

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Answer:

[tex]W=-251096.465\ J[/tex] negativesign denotes thatthe work is consumed by the system.

Explanation:

Given:

Isothermal process.

initial temperature, [tex]T_1=300\ K[/tex]

initial pressure, [tex]P_1=150kPa[/tex]

initial volume, [tex]V_1=0.2\ m^3[/tex]

final pressure, [tex]P_2=800\ kPa[/tex]

The work done during an isothermal process is given by:

Answer:[tex]W=-251096.465\ J[/tex] negativesign denotes thatthe work is consumed by the system.

Explanation:Given:

Isothermal process.

initial temperature, [tex]T_1=300\ K[/tex]

initial pressure, [tex]P_1=150kPa[/tex]

initial volume, [tex]V_1=0.2\ m^3[/tex]

final pressure, [tex]P_2=800\ kPa[/tex]

The work done during an isothermal process is given by:[tex]W=P_1.V_1\times ln(\frac{P_1}{P_2} )[/tex]

[tex]W=150\times 1000\times \ln\frac{150}{800}[/tex]

[tex]W=-251096.465\ J[/tex] negativesign denotes thatthe work is consumed by the system.