Mr. Barcena reached a top speed of 5m/s in 2 seconds from rest, what was his average acceleration including units?
correct answer is not here
.25
OO00
5.2
2.5
Question
Question
Mr. Barcena reached a top speed of 5m/s in 2 seconds from rest, what was his average acceleration including units?
correct answer is not here
.25
OO00
5.2
2.5
Answer:
Explanation:
The equation for acceleration is
[tex]a=\frac{v_f-v_0}{t}[/tex] where vf is the final velocity and v0 is the initial velocity. Filling in:
[tex]a=\frac{5-0}{2}[/tex] so
a = 2.5 m/s/s