Step-by-step explanation:

Given that,

The diameter of the merry-go-round, d = 14 feet

Time taken, t = 6 seconds

Radius, r = 7 feet

The linear speed of the merry-go-round is given by :

[tex]v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 7}{6}\\\\=7.33\ m/s[/tex]

Also,

[tex]v=r\omega[/tex]

Where

[tex]\omega[/tex] is the angular speed

So,

[tex]\omega=\dfrac{v}{r}\\\\\omega=\dfrac{7.33}{7}\\\\=1.04\ rad/s[/tex]

Hence, his linear and angular speeds are 7.33 m/s and 1.04 rad/s.