Look at this balanced chemical reaction: N2 + 3H2 2NH3 How many grams of ammonia can be produced from reacting a 450 L sample of

Question

Look at this balanced chemical reaction: N2 + 3H2 2NH3

How many grams of ammonia can be produced from reacting a 450 L sample of nitrogen gas at a temperature of 450 K and a pressure of 300 atm?

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Jezebel 5 years 2021-07-12T19:57:42+00:00 1 Answers 24 views 0

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  1. Calantha
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    2021-07-12T19:59:28+00:00
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    Answer: A mass of 124457.96 g ammonia is produced by reacting a 450 L sample of nitrogen gas at a temperature of 450 K and a pressure of 300 atm.

    Explanation:

    Given: Volume = 450 L

    Temperature = 450 K

    Pressure = 300 atm

    Using ideal gas equation, moles of nitrogen are calculated as follows.

    PV = nRT

    where,

    P = pressure

    V = volume

    n = no. of moles

    R = gas constant = 0.0821 L atm/mol K

    T = tempertaure

    Substitute values into the above formula as follows.

    PV = nRT\\300 atm \times 450 L = n \times 0.0821 L atm/mol K \times 450 K\\n = \frac{135000}{36.945}\\= 3654.08 mol

    According to the given equation, 1 mole of nitrogen forms 2 moles of ammonia. So, moles of ammonia formed by 3654.08 moles of nitrogen is as follows.

    2 \times 3654.08 mol\\= 7308.16 mol

    As moles is the mass of substance divided by its molar mass. So, mass of ammonia (molar mass = 17.03 g/mol) is as follows.

    Moles = \frac{mass}{molar mass}\\7308.16 = \frac{mass}{17.03 g/mol}\\mass = 124457.96 g

    Thus, we can conclude that a mass of 124457.96 g ammonia is produced by reacting a 450 L sample of nitrogen gas at a temperature of 450 K and a pressure of 300 atm.

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