$\left \{ {{x^2+y^2=2x^2y^2} \atop {x+y-3xy+1=0}} \right.$

Question

$\left \{ {{x^2+y^2=2x^2y^2} \atop {x+y-3xy+1=0}} \right.$

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Bình An 5 years 2021-05-24T02:30:45+00:00 1 Answers 26 views 0

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  1. Sapo1
    0
    2021-05-24T02:32:04+00:00
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    Đáp án: $(x;y)=(1;1)$

     

     

    left-2-y-2-2-2y-2-atop-y-3y-1-0-right

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )