# lam ho mk voi a ( bai 5)

lam ho mk voi a ( bai 5)

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1. giahung

$$\begin{array}{l} a){a^3} + 3.{a^2}.4 + 3.a{.4^2} + {4^3}\\ = {\left( {a + 4} \right)^3}\\ b. – \left( {{b^3} – 3.{b^2}.2 + 3.b.4 – {2^3}} \right)\\ = – {\left( {b – 2} \right)^3}\\ c.{\left( {m – n} \right)^6} – 3.{\left( {m – n} \right)^4}.2 + 3.{\left( {m – n} \right)^2}.4 – {2^3}\\ = {\left[ {{{\left( {m – n} \right)}^2} – 2} \right]^3}\\ d.{\left( {\dfrac{2}{3}a} \right)^3} – 3.{\left( {\dfrac{2}{3}a} \right)^2}.2b + 3.\left( {\dfrac{2}{3}a} \right).4{b^2} – {\left( {2b} \right)^3}\\ = {\left( {\dfrac{2}{3}a – 2b} \right)^3} \end{array}$$

d. $${\left( {\dfrac{2}{3}a – 2b} \right)^3}$$
$$\begin{array}{l} a){a^3} + 3.{a^2}.4 + 3.a{.4^2} + {4^3}\\ = {\left( {a + 4} \right)^3}\\ b. – \left( {{b^3} – 3.{b^2}.2 + 3.b.4 – {2^3}} \right)\\ = – {\left( {b – 2} \right)^3}\\ c.{\left( {m – n} \right)^6} – 3.{\left( {m – n} \right)^4}.2 + 3.{\left( {m – n} \right)^2}.4 – {2^3}\\ = {\left[ {{{\left( {m – n} \right)}^2} – 2} \right]^3}\\ d.{\left( {\dfrac{2}{3}a} \right)^3} – 3.{\left( {\dfrac{2}{3}a} \right)^2}.2b + 3.\left( {\dfrac{2}{3}a} \right).4{b^2} – {\left( {2b} \right)^3}\\ = {\left( {\dfrac{2}{3}a – 2b} \right)^3} \end{array}$$