Làm giúp mk mn ơi …..

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Làm giúp mk mn ơi
…..
lam-giup-mk-mn-oi

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Khải Quang 4 years 2020-10-15T09:02:01+00:00 2 Answers 100 views 0

Answers ( )

  1. Farah
    0
    2020-10-15T09:03:05+00:00
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    $a)4x^2+x⇔x.(4x+1)_{}$

    $b)3x-9y⇔3.(x-3y)_{}$

    $c)5.(x-y)-x(x-y)⇔(5-x)(x-y)_{}$

    $d)3(2x-y)-x(y-2x)_{}$

    $⇔4(2x-y)+x(2x-y)_{}$

    $⇔(2x-y)(4+x)_{}$

    $e)(2x+1)^2+2(2x+1)_{}$

    $⇔(2x+1)(2x+1+2)_{}$

    $⇔(2x+1)(2x+3)_{}$

    $f)(x^2-9)+3(x-3)_{}$

    $⇔(x-3)(x+3)+3(x-3)_{}$

    $⇔(x-3)(x+3+3)_{}$

    $⇔(x-3)(x+6)_{}$

    $g)(x-y)^2+2y.(y-x)^2_{}$

    $⇔(x-y)(x-y-2y)_{}$

    $⇔(x-y)(x-3y)_{}$

  2. kiet
    0
    2020-10-15T09:03:51+00:00
    Reply

    Đáp án:

     

    Giải thích các bước giải:

     a) `4x^2+x=x(4x+1)`

    b) `3x-9y=3(x-3y)`

    c) `5(x-y)-x(x-y)=(5-x)(x-y)`

    d) `4(2x-y)-x(y-2x)=(2x-y)(4+x)`

    e) `(2x+1)^2+2(2x+1)=(2x+1)(2x+1+2)=(2x+1)(2x+3)`

    f) `(x^2-9)+3(x-3)=(x-3)(x+3)+3(x-3)=(x-3)(x+3+3)=(x-3)(x+6)`

    g) `(x-y)^2+2y(y-x)^2=(x-y)(x-y-2y)=(x-y)(x-3y)`

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