Làm giúp mk mn ơi ….. Question Làm giúp mk mn ơi ….. in progress 0 Môn Toán Khải Quang 4 years 2020-10-15T09:02:01+00:00 2020-10-15T09:02:01+00:00 2 Answers 100 views 0
Answers ( )
$a)4x^2+x⇔x.(4x+1)_{}$
$b)3x-9y⇔3.(x-3y)_{}$
$c)5.(x-y)-x(x-y)⇔(5-x)(x-y)_{}$
$d)3(2x-y)-x(y-2x)_{}$
$⇔4(2x-y)+x(2x-y)_{}$
$⇔(2x-y)(4+x)_{}$
$e)(2x+1)^2+2(2x+1)_{}$
$⇔(2x+1)(2x+1+2)_{}$
$⇔(2x+1)(2x+3)_{}$
$f)(x^2-9)+3(x-3)_{}$
$⇔(x-3)(x+3)+3(x-3)_{}$
$⇔(x-3)(x+3+3)_{}$
$⇔(x-3)(x+6)_{}$
$g)(x-y)^2+2y.(y-x)^2_{}$
$⇔(x-y)(x-y-2y)_{}$
$⇔(x-y)(x-3y)_{}$
Đáp án:
Giải thích các bước giải:
a) `4x^2+x=x(4x+1)`
b) `3x-9y=3(x-3y)`
c) `5(x-y)-x(x-y)=(5-x)(x-y)`
d) `4(2x-y)-x(y-2x)=(2x-y)(4+x)`
e) `(2x+1)^2+2(2x+1)=(2x+1)(2x+1+2)=(2x+1)(2x+3)`
f) `(x^2-9)+3(x-3)=(x-3)(x+3)+3(x-3)=(x-3)(x+3+3)=(x-3)(x+6)`
g) `(x-y)^2+2y(y-x)^2=(x-y)(x-y-2y)=(x-y)(x-3y)`