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Jello has a density of 1.14 g/mL. A box of Jello makes 475 mL of Jello and has 13 g of sugar. Determine the % m/m of sugar in the Jello. (Hi
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Answer:
2.34 %
Explanation:
Since the density of the Jello, ρ = 1.14 g/mL and ρ = m/v where m = mass of jello and v = volume of jello = 475 mL.
So, m = ρv
substituting the values of the variables into the equation, we have
m = ρv
m = 1.14 g/mL × 475 mL = 541.5 g
Since we have 13 g of sugar in the jello, the total mass present is 13 g + 541.5 g = 554.5 g
So, the percentage by mass of sugar present % m/m = mass of sugar present/total mass × 100 %
= 13 g/554.5 g × 100 %
= 0.0234 × 100 %
= 2.34 %
So, the percentage by mass of sugar present % m/m = 2.34 %