Initially stationary, a train has a constant acceleration of 0.8 m/s2. (a) What is its speed after 27 s? m/s (b) What is the total time requ

Question

Initially stationary, a train has a constant acceleration of 0.8 m/s2. (a) What is its speed after 27 s? m/s (b) What is the total time required for the train to reach a speed of 41 m/s?

in progress 0
Nho 5 years 2021-08-18T04:36:22+00:00 1 Answers 21 views 0

Answers ( )

  1. niczorrrr
    0
    2021-08-18T04:37:44+00:00
    Reply

    Answer:

    (a) v1 = 21.6 m/s

    (b) t = 51.25 s

    Explanation:

    Use kinematics equation

    v1 = v0 + at

    Given

    v0 = 0 = initial velocity

    a = 0.8 m/s^2 = acceleration

    (a) t = 27 seconds

    v1 = v0 + at = 0 + 0.8*27 = 21.6 m/s

    (b) v1 = 41 m/s

    v1 = v0 + at

    solve for t

    t = (v1-v0)/a = (41-0)/0.8 = 51.25 s

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )