In the Bohr theory of the hydrogen atom, an electron moves in a circular orbit about a proton, assume the radius of the orbit is 5.29 10-11

Question

In the Bohr theory of the hydrogen atom, an electron moves in a circular orbit about a proton, assume the radius of the orbit is 5.29 10-11 m. (a) Find the magnitude of the electric force exerted on each particle.

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Thu Cúc 5 years 2021-08-15T03:41:12+00:00 1 Answers 24 views 0

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  1. minhkhue
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    2021-08-15T03:42:37+00:00
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    Answer:

    F=9.06*10^{-8} N

    Explanation:

    We can use the Coulomb force

    F=k\frac{q_{e}q_{p}}{r^{2}}

    F=9*10^{9}\frac{|-(1.6*10^{-19})^{2}|}{(5.29*10^{11})^{2}}

    F=9.06*10^{-8} N

    The direction of the force is toward proton with respect to the electron reference coordinate and is in the direction of the electron in the proton system reference.

    I hope it helps you!

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