In an experiment, one of the forces exerted on a proton is F⃗ =−αx2i^, where α=12N/m2. What is the potential-energy function for F⃗ ? Let U=0 when x=0.

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Answer:The potential energy is

Explanation:Given that,Force

We need to calculate the potential energyUsing formula of work donePut the value of F

On integration

…(I)

U = 0, x = 0 so C = 0

Put the value of c and α in equation (I)

Hence, The potential energy is