If the price of 12 shirts is rupees 3600 3/5 and of 6 pants is rupees 3000 1/5 . Find the price of 4 shirts and 4 pants

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Mathematics Farah 4 years 2021-08-09T10:48:47+00:00 2021-08-09T10:48:47+00:00 1 Answers 46 views 0

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Doris · Answer 1 · 2021-08-09T10:50:02+00:00

Given:

Price of 12 shirts = Rs. $3600\dfrac{3}{5}$

Price of 6 pants = Rs. $3000\dfrac{1}{5}$

To find:

The price of 4 shirts and 4 pants.

Solution:

It is given that,

Price of 12 shirts = Rs. $3600\dfrac{3}{5}$

Price of 1 shirt = Rs. $\dfrac{1}{12}\times 3600\dfrac{3}{5}$

Price of 4 shirts = Rs. $\dfrac{4}{12}\times 3600\dfrac{3}{5}$

= Rs. $\dfrac{1}{3}\times \dfrac{18003}{5}$

= Rs. $\dfrac{18003}{15}$

Price of 6 pants = Rs. $3000\dfrac{1}{5}$

Price of 1 pant = Rs. $\dfrac{1}{6}\times 3000\dfrac{1}{5}$

Price of 4 pants = Rs. $\dfrac{4}{6}\times 3000\dfrac{1}{5}$

= Rs. $\dfrac{2}{3}\times \dfrac{15001}{5}$

= Rs. $\dfrac{30002}{15}$

Now, the price of 4 shirts and 4 pants is:

$\text{Required price}=\dfrac{18003}{15}+\dfrac{30002}{15}$

$\text{Required price}=\dfrac{48005}{15}$

$\text{Required price}=\dfrac{9601}{3}$

$\text{Required price}=3200\dfrac{1}{3}$

Therefore, the price of 4 shirts and 4 pants is Rs. $3200\dfrac{1}{3}$ .