Given:

Price of 12 shirts = Rs. [tex]3600\dfrac{3}{5}[/tex]

Price of 6 pants = Rs. [tex]3000\dfrac{1}{5}[/tex]

To find:

The price of 4 shirts and 4 pants​.

Solution:

It is given that,

Price of 12 shirts = Rs. [tex]3600\dfrac{3}{5}[/tex]

Price of 1 shirt = Rs. [tex]\dfrac{1}{12}\times 3600\dfrac{3}{5}[/tex]

Price of 4 shirts = Rs. [tex]\dfrac{4}{12}\times 3600\dfrac{3}{5}[/tex]

                          = Rs. [tex]\dfrac{1}{3}\times \dfrac{18003}{5}[/tex]

                          = Rs. [tex]\dfrac{18003}{15}[/tex]

Price of 6 pants = Rs. [tex]3000\dfrac{1}{5}[/tex]

Price of 1 pant = Rs. [tex]\dfrac{1}{6}\times 3000\dfrac{1}{5}[/tex]

Price of 4 pants = Rs. [tex]\dfrac{4}{6}\times 3000\dfrac{1}{5}[/tex]

                          = Rs. [tex]\dfrac{2}{3}\times \dfrac{15001}{5}[/tex]

                          = Rs. [tex]\dfrac{30002}{15}[/tex]

Now, the price of 4 shirts and 4 pants​ is:

[tex]\text{Required price}=\dfrac{18003}{15}+\dfrac{30002}{15}[/tex]

[tex]\text{Required price}=\dfrac{48005}{15}[/tex]

[tex]\text{Required price}=\dfrac{9601}{3}[/tex]

[tex]\text{Required price}=3200\dfrac{1}{3}[/tex]

Therefore, the price of 4 shirts and 4 pants​ is Rs. [tex]3200\dfrac{1}{3}[/tex].