If 18 is subtracted from twice the square of an integer, the
result is equal to nine times the integer. Find the integer.
[Only an algebraic solution will be accepted.]


  1. Answer:


    Step-by-step explanation:

    Let x = the integer:

    2x^2 – 18 = 9x

    2x^2 – 9x – 18 = 0

    Now either factor that or use the quadratic formula if you’re lazy like me.

    x = -3/2 and 6, so x must be 6 because it has to be an integer.

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