If 18 is subtracted from twice the square of an integer, the
result is equal to nine times the integer. Find the integer.
[Only an algebraic solution will be accepted.]
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Question
If 18 is subtracted from twice the square of an integer, the
result is equal to nine times the integer. Find the integer.
[Only an algebraic solution will be accepted.]
You must be logged in to post a comment.
Answer:
-3/2
Step-by-step explanation:
Let x = the integer:
2x^2 – 18 = 9x
2x^2 – 9x – 18 = 0
Now either factor that or use the quadratic formula if you’re lazy like me.
x = -3/2 and 6, so x must be 6 because it has to be an integer.