Given r=3 and a center of (3,5)? Find the equation of the circle in standard and general form.

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Given r=3 and a center of (3,5)? Find the equation of the circle in standard and general form.

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RobertKer 4 years 2021-08-29T00:35:54+00:00 1 Answers 11 views 0

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  1. Philomena
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    2021-08-29T00:37:07+00:00
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    9514 1404 393

    Answer:

    • (x -3)^2 +(y -5)^2 = 9
    • x^2 +y^2 -6x -10y +25 = 0

    Step-by-step explanation:

    The standard form equation for a circle of radius r and center (h, k) is …

      (x -h)^2 +(y -k)^2 = r^2

    For radius 3 and center (3, 5), this is …

      (x -3)^2 +(y -5)^2 = 9 . . . . standard form equation

    Expanding this and subtracting the constant on the right gives …

      x^2 -6x +9 +y^2 -10y +25 -9 = 0

      x^2 +y^2 -6x -10y +25 = 0 . . . . general form equation

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