Question Given r=3 and a center of (3,5)? Find the equation of the circle in standard and general form.
9514 1404 393 Answer: (x -3)^2 +(y -5)^2 = 9 x^2 +y^2 -6x -10y +25 = 0 Step-by-step explanation: The standard form equation for a circle of radius r and center (h, k) is … (x -h)^2 +(y -k)^2 = r^2 For radius 3 and center (3, 5), this is … (x -3)^2 +(y -5)^2 = 9 . . . . standard form equation Expanding this and subtracting the constant on the right gives … x^2 -6x +9 +y^2 -10y +25 -9 = 0 x^2 +y^2 -6x -10y +25 = 0 . . . . general form equation Log in to Reply
9514 1404 393
Answer:
Step-by-step explanation:
The standard form equation for a circle of radius r and center (h, k) is …
(x -h)^2 +(y -k)^2 = r^2
For radius 3 and center (3, 5), this is …
(x -3)^2 +(y -5)^2 = 9 . . . . standard form equation
Expanding this and subtracting the constant on the right gives …
x^2 -6x +9 +y^2 -10y +25 -9 = 0
x^2 +y^2 -6x -10y +25 = 0 . . . . general form equation