Giúp mk vs ạ ĐUzirs4is8rsrziris8rs7ra6az6ssuususussu

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Giúp mk vs ạ
ĐUzirs4is8rsrziris8rs7ra6az6ssuususussu
giup-mk-vs-a-duzirs4is8rsrziris8rs7ra6az6ssuususussu

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Dâu 5 years 2021-05-16T22:21:00+00:00 1 Answers 31 views 0

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  1. minhkhang
    0
    2021-05-16T22:22:15+00:00
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    $\displaystyle\lim_{x \to 1} \dfrac{f(x)-10}{x-1}=5\\ \Rightarrow f(x)-10=(x-1)g(x)\\ \Rightarrow \displaystyle\lim_{x \to 1} g(x)=g(1)=5\\ f(x)-10=(x-1)g(x); x=1\Rightarrow f(1)-10=0 \Leftrightarrow f(1)=10\\ I=\displaystyle\lim_{x \to 1} \dfrac{f(x)-10}{(x-1)\sqrt{4f(x)+9}+3}\\ =\displaystyle\lim_{x \to 1} \dfrac{g(x)}{\sqrt{4f(x)+9}+3}\\ =\displaystyle\lim_{x \to 1} \dfrac{g(1)}{\sqrt{4f(1)+9}+3}\\ =\dfrac{g(1)}{\sqrt{4f(1)+9}+3}\\ =\dfrac{5}{\sqrt{4.10+9}+3}\\ =\dfrac{1}{2}$

     

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