Giúp mk vs ạ cảm ơn bạn nhiều lắm Question Giúp mk vs ạ cảm ơn bạn nhiều lắm in progress 0 Môn Toán Tryphena 4 years 2020-11-01T09:09:18+00:00 2020-11-01T09:09:18+00:00 1 Answers 67 views 0
Answers ( )
Đáp án:
$\begin{array}{l}
a){x^2} + 5x – 6\\
= {x^2} + 6x – x – 6\\
= \left( {x + 6} \right)\left( {x – 1} \right)\\
b){x^2} – 7x + 10\\
= {x^2} – 2x – 5x + 10\\
= \left( {x – 2} \right)\left( {x – 5} \right)\\
c){x^3} + {x^2} – 3x – 27\\
= {x^3} – 27 + {x^2} – 3x\\
= \left( {x – 3} \right)\left( {{x^2} + 3x + 9} \right) + x\left( {x – 3} \right)\\
= \left( {x – 3} \right)\left( {{x^2} + 3x + 9 + x} \right)\\
= \left( {x – 3} \right)\left( {{x^2} + 4x + 9} \right)\\
d)2{x^3} + 3{x^2} – 2x\\
= x.\left( {2{x^2} + 3x – 2} \right)\\
= x\left( {2{x^2} + 4x – x – 2} \right)\\
= x\left( {x + 2} \right)\left( {2x – 1} \right)\\
e){x^2} – xz – 9{y^2} + 3yz\\
= {x^2} – 9{y^2} + 3yz – xz\\
= \left( {x – 3y} \right)\left( {x + 3y} \right) – z\left( {x – 3y} \right)\\
= \left( {x – 3y} \right)\left( {x + 3y – z} \right)\\
f)\left( {x + 1} \right)\left( {x + 2} \right)\left( {x + 3} \right)\left( {x + 4} \right) – 120\\
= \left( {x + 1} \right)\left( {x + 4} \right)\left( {x + 2} \right)\left( {x + 3} \right) – 120\\
= \left( {{x^2} + 5x + 4} \right)\left( {{x^2} + 5x + 6} \right) – 120\\
Dat:{x^2} + 5x + 4 = a\\
\Rightarrow a.\left( {a + 2} \right) – 120\\
= {a^2} + 2a – 120\\
= {a^2} + 12a – 10a – 120\\
= \left( {a + 12} \right)\left( {a – 10} \right)\\
= \left( {{x^2} + 5x + 4 + 12} \right)\left( {{x^2} + 5x + 4 – 10} \right)\\
= \left( {{x^2} + 5x + 16} \right)\left( {{x^2} + 5x – 6} \right)\\
g){x^3} – 5{x^2} – 4x + 20\\
= {x^2}\left( {x – 5} \right) – 4\left( {x – 5} \right)\\
= \left( {x – 5} \right)\left( {{x^2} – 4} \right)\\
= \left( {x – 5} \right)\left( {x – 2} \right)\left( {x + 2} \right)
\end{array}$