giúp em với mọi người em đang cần gấp ạ

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giúp em với mọi người
em đang cần gấp ạ
giup-em-voi-moi-nguoi-em-dang-can-gap-a

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Dâu 5 years 2020-10-26T03:34:40+00:00 2 Answers 99 views 0

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    0
    2020-10-26T03:36:07+00:00

    13) x²-x-y²-y

    = x²-y²-x-y

    = (x²-y²)-(x+y)

    = (x-y)(x+y)-(x+y)

    = (x-y-1)(x+y)

    14) x²-2xy+y²-z²

    = (x-y)²-z²

    = (x-y-z)(x-y+z)

    15) a³-a²x-ay+xy

    = a²(a-x)-y(a-x)

    = (a²-y)(a-x)

    16) x²-2xy-4z²+y²

    = (x²-2xy+y²)-4z²

    = (x-y)²-(2z)²

    = (x-y-2z)(x-y+2z)

    17) 4x²-y²+4x+1

    = (4x²+4x+1)-y²

    = (2x+1)²-y²

    = (2x+1-y)(2x+1+y)

    18) x³-x+y³-y

    = (x³+y³)-(x+y)

    = (x+y)(x²-xy+y²)-(x+y)

    = (x+y)(x²-xy+y²-1)

    19) $x^{4}$ +2x³+x²

    = x²(x²+2x+1)

    = x²(x+1)²

    20) 5x²-10xy+5y²-20z²

    = 5(x²-2xy+y²-4z²)

    = 5[(x+y)²-(2z)²]

    = 5(x+y-2z)(x+y+2z)

    21) x³-x+3x²y+3xy²+y³-y

    = (x³+3x²y+3xy²+y³)-(x+y)

    = (x+y)³-(x+y) 

    = (x+y) (x+y+1)(x+y-1)

     

    0
    2020-10-26T03:36:32+00:00

    Đáp án: $13)(x+y)(x-y-1)$

                 $14)(x-y-z)(x-y+z)$

                 $15)(a^2-y)(a-x)$

                 $16)(x-y-2z)(x-y+2z)$

                 $17)(2x+1-y)(2x+1+y)$

                 $18)(x+y)(x^2-xy+y^2-1)$

                 $19)x^2(x+1)^2$

                 $20)5(x-y-2z)(x-y+2z)$

                 $21)(x+y)(x+y-1)(x+y+1)$

    Giải thích các bước giải:

    $13)x^2-x-y^2-y$

    $=(x^2-y^2)-(x+y)$

    $=(x-y)(x+y)-(x+y)$

    $=(x+y)(x-y-1)$

    $14)x^2-2xy+y^2-z^2$

    $=(x^2-2xy+y^2)-z^2$

    $=(x-y)^2-z^2$

    $=(x-y-z)(x-y+z)$

    $15)a^3-a^2x-ay+xy$

    $=(a^3-a^2x)-(ay-xy)$

    $=a^2(a-x)-y(a-x)$

    $=(a^2-y)(a-x)$

    $16)x^2-2xy-4z^2+y^2$

    $=(x^2-2xy+y^2)-4z^2$

    $=(x-y)^2-(2z)^2$

    $=(x-y-2z)(x-y+2z)$

    $17)4x^2-y^2+4x+1$

    $=(4x^2+4x+1)-y^2$

    $=(2x+1)^2-y^2$

    $=(2x+1-y)(2x+1+y)$

    $18)x^3-x+y^3-y$

    $=(x^3+y^3)-(x+y)$

    $=(x+y)(x^2-xy+y^2)-(x+y)$

    $=(x+y)(x^2-xy+y^2-1)$

    $19)x^4+2x^3+x^2$

    $=x^2(x^2+2x+1)$

    $=x^2(x+1)^2$

    $20)5x^2-10xy+5y^2-20z^2$

    $=5(x^2-2xy+y^2-4z^2)$

    $=5[(x^2-2xy+y^2)-4z^2]$

    $=5[(x-y)^2-(2z)^2]$

    $=5(x-y-2z)(x-y+2z)$

    $21)x^3-x+3x^2y+3xy^2+y^3-y$

    $=(x^3+3x^2y+3xy^2+y^3)-(x+y)$

    $=(x+y)^3-(x+y)$

    $=(x+y)[(x+y)^2-1]$

    $=(x+y)(x+y-1)(x+y+1)$

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