Dâu 863 Questions 2k Answers 0 Best Answers 17 Points View Profile0 Dâu Asked: Tháng Mười 26, 20202020-10-26T03:34:40+00:00 2020-10-26T03:34:40+00:00In: Môn Toángiúp em với mọi người em đang cần gấp ạ0giúp em với mọi người em đang cần gấp ạ ShareFacebookRelated Questions Một hình thang có đáy lớn là 52cm ; đáy bé kém đáy lớn 16cm ; chiều cao kém đáy ... Useful news and important articles APROTININ FROM BOVINE LUNG CELL CULTURE купить онлайн2 AnswersOldestVotedRecentTryphena 858 Questions 2k Answers 0 Best Answers 19 Points View Profile Tryphena 2020-10-26T03:36:07+00:00Added an answer on Tháng Mười 26, 2020 at 3:36 sáng 13) x²-x-y²-y= x²-y²-x-y= (x²-y²)-(x+y)= (x-y)(x+y)-(x+y)= (x-y-1)(x+y)14) x²-2xy+y²-z²= (x-y)²-z²= (x-y-z)(x-y+z)15) a³-a²x-ay+xy= a²(a-x)-y(a-x)= (a²-y)(a-x)16) x²-2xy-4z²+y²= (x²-2xy+y²)-4z²= (x-y)²-(2z)²= (x-y-2z)(x-y+2z)17) 4x²-y²+4x+1= (4x²+4x+1)-y²= (2x+1)²-y²= (2x+1-y)(2x+1+y)18) x³-x+y³-y= (x³+y³)-(x+y)= (x+y)(x²-xy+y²)-(x+y)= (x+y)(x²-xy+y²-1)19) $x^{4}$ +2x³+x²= x²(x²+2x+1)= x²(x+1)²20) 5x²-10xy+5y²-20z²= 5(x²-2xy+y²-4z²)= 5[(x+y)²-(2z)²]= 5(x+y-2z)(x+y+2z)21) x³-x+3x²y+3xy²+y³-y= (x³+3x²y+3xy²+y³)-(x+y)= (x+y)³-(x+y) = (x+y) (x+y+1)(x+y-1) 0Reply Share ShareShare on FacebookKing 854 Questions 2k Answers 0 Best Answers 24 Points View Profile King 2020-10-26T03:36:32+00:00Added an answer on Tháng Mười 26, 2020 at 3:36 sáng Đáp án: $13)(x+y)(x-y-1)$ $14)(x-y-z)(x-y+z)$ $15)(a^2-y)(a-x)$ $16)(x-y-2z)(x-y+2z)$ $17)(2x+1-y)(2x+1+y)$ $18)(x+y)(x^2-xy+y^2-1)$ $19)x^2(x+1)^2$ $20)5(x-y-2z)(x-y+2z)$ $21)(x+y)(x+y-1)(x+y+1)$Giải thích các bước giải:$13)x^2-x-y^2-y$$=(x^2-y^2)-(x+y)$$=(x-y)(x+y)-(x+y)$$=(x+y)(x-y-1)$$14)x^2-2xy+y^2-z^2$$=(x^2-2xy+y^2)-z^2$$=(x-y)^2-z^2$$=(x-y-z)(x-y+z)$$15)a^3-a^2x-ay+xy$$=(a^3-a^2x)-(ay-xy)$$=a^2(a-x)-y(a-x)$$=(a^2-y)(a-x)$$16)x^2-2xy-4z^2+y^2$$=(x^2-2xy+y^2)-4z^2$$=(x-y)^2-(2z)^2$$=(x-y-2z)(x-y+2z)$$17)4x^2-y^2+4x+1$$=(4x^2+4x+1)-y^2$$=(2x+1)^2-y^2$$=(2x+1-y)(2x+1+y)$$18)x^3-x+y^3-y$$=(x^3+y^3)-(x+y)$$=(x+y)(x^2-xy+y^2)-(x+y)$$=(x+y)(x^2-xy+y^2-1)$$19)x^4+2x^3+x^2$$=x^2(x^2+2x+1)$$=x^2(x+1)^2$$20)5x^2-10xy+5y^2-20z^2$$=5(x^2-2xy+y^2-4z^2)$$=5[(x^2-2xy+y^2)-4z^2]$$=5[(x-y)^2-(2z)^2]$$=5(x-y-2z)(x-y+2z)$$21)x^3-x+3x^2y+3xy^2+y^3-y$$=(x^3+3x^2y+3xy^2+y^3)-(x+y)$$=(x+y)^3-(x+y)$$=(x+y)[(x+y)^2-1]$$=(x+y)(x+y-1)(x+y+1)$0Reply Share ShareShare on FacebookLeave an answerLeave an answerHủy By answering, you agree to the Terms of Service and Privacy Policy .* Lưu tên của tôi, email, và trang web trong trình duyệt này cho lần bình luận kế tiếp của tôi.
Tryphena
13) x²-x-y²-y
= x²-y²-x-y
= (x²-y²)-(x+y)
= (x-y)(x+y)-(x+y)
= (x-y-1)(x+y)
14) x²-2xy+y²-z²
= (x-y)²-z²
= (x-y-z)(x-y+z)
15) a³-a²x-ay+xy
= a²(a-x)-y(a-x)
= (a²-y)(a-x)
16) x²-2xy-4z²+y²
= (x²-2xy+y²)-4z²
= (x-y)²-(2z)²
= (x-y-2z)(x-y+2z)
17) 4x²-y²+4x+1
= (4x²+4x+1)-y²
= (2x+1)²-y²
= (2x+1-y)(2x+1+y)
18) x³-x+y³-y
= (x³+y³)-(x+y)
= (x+y)(x²-xy+y²)-(x+y)
= (x+y)(x²-xy+y²-1)
19) $x^{4}$ +2x³+x²
= x²(x²+2x+1)
= x²(x+1)²
20) 5x²-10xy+5y²-20z²
= 5(x²-2xy+y²-4z²)
= 5[(x+y)²-(2z)²]
= 5(x+y-2z)(x+y+2z)
21) x³-x+3x²y+3xy²+y³-y
= (x³+3x²y+3xy²+y³)-(x+y)
= (x+y)³-(x+y)
= (x+y) (x+y+1)(x+y-1)
King
Đáp án: $13)(x+y)(x-y-1)$
$14)(x-y-z)(x-y+z)$
$15)(a^2-y)(a-x)$
$16)(x-y-2z)(x-y+2z)$
$17)(2x+1-y)(2x+1+y)$
$18)(x+y)(x^2-xy+y^2-1)$
$19)x^2(x+1)^2$
$20)5(x-y-2z)(x-y+2z)$
$21)(x+y)(x+y-1)(x+y+1)$
Giải thích các bước giải:
$13)x^2-x-y^2-y$
$=(x^2-y^2)-(x+y)$
$=(x-y)(x+y)-(x+y)$
$=(x+y)(x-y-1)$
$14)x^2-2xy+y^2-z^2$
$=(x^2-2xy+y^2)-z^2$
$=(x-y)^2-z^2$
$=(x-y-z)(x-y+z)$
$15)a^3-a^2x-ay+xy$
$=(a^3-a^2x)-(ay-xy)$
$=a^2(a-x)-y(a-x)$
$=(a^2-y)(a-x)$
$16)x^2-2xy-4z^2+y^2$
$=(x^2-2xy+y^2)-4z^2$
$=(x-y)^2-(2z)^2$
$=(x-y-2z)(x-y+2z)$
$17)4x^2-y^2+4x+1$
$=(4x^2+4x+1)-y^2$
$=(2x+1)^2-y^2$
$=(2x+1-y)(2x+1+y)$
$18)x^3-x+y^3-y$
$=(x^3+y^3)-(x+y)$
$=(x+y)(x^2-xy+y^2)-(x+y)$
$=(x+y)(x^2-xy+y^2-1)$
$19)x^4+2x^3+x^2$
$=x^2(x^2+2x+1)$
$=x^2(x+1)^2$
$20)5x^2-10xy+5y^2-20z^2$
$=5(x^2-2xy+y^2-4z^2)$
$=5[(x^2-2xy+y^2)-4z^2]$
$=5[(x-y)^2-(2z)^2]$
$=5(x-y-2z)(x-y+2z)$
$21)x^3-x+3x^2y+3xy^2+y^3-y$
$=(x^3+3x^2y+3xy^2+y^3)-(x+y)$
$=(x+y)^3-(x+y)$
$=(x+y)[(x+y)^2-1]$
$=(x+y)(x+y-1)(x+y+1)$