g Monochromatic light with wavelength 633 nn passes through a narrow slit and a patternappears on a screen 6.0 m away. The distance on the s

Question

g Monochromatic light with wavelength 633 nn passes through a narrow slit and a patternappears on a screen 6.0 m away. The distance on the screen between the centers of thefirst minima on either side of the screen is 32 mm. How wide (in mm) is the slit

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Ngọc Hoa 5 years 2021-08-06T01:36:56+00:00 1 Answers 25 views 0

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  1. yenoanh
    0
    2021-08-06T01:38:31+00:00
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    Answer:

    d = 1.19 x 10⁻⁴ m = 0.119 mm

    Explanation:

    This problem can be solved by using Young’s double-slit experiment formula:

    Y = \frac{\lambda L}{d}

    where,

    Y = fringe spacing = 32 mm = 0.032 m

    L = slit to screen distance = 6 m

    λ = wavelength of light = 633 nm = 6.33 x 10⁻⁷ m

    d = slit width = ?

    Therefore,

    0.032\ m = \frac{(6.33\ x\ 10^{-7}\ m)(6\ m)}{d}\\\\d = \frac{(6.33\ x\ 10^{-7}\ m)(6\ m)}{0.032\ m}

    d = 1.19 x 10⁻⁴ m = 0.119 mm

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