g A centripetal force F is applied to an object moving at a constant speed v in a horizontal circle of radius r. If the radius is quadrupled

Question

g A centripetal force F is applied to an object moving at a constant speed v in a horizontal circle of radius r. If the radius is quadrupled and the speed is doubled, what happens to the centripetal force

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Vodka 5 years 2021-08-17T15:24:02+00:00 1 Answers 154 views 0

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  1. thanhha
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    2021-08-17T15:25:52+00:00
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    Answer:

    The centripetal force remains constant.

    Explanation:

    The magnitude of centripetal force is given by the following formula:

    F = mv²/r

    where,

    F = Centripetal Force

    m = mass of the object

    v = velocity of the object

    r = radius of the circle

    Now, if we quadruple the radius (r = 4r) and the speed is doubled (v = 2v). Then the centripetal force becomes:

    F’ = m(2 v)²/4r

    F’ = (4/4)(mv²/r)

    F’ = mv²/r

    F’ = F

    Thus, the centripetal force remain constant.

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