g 12. Spring A has a spring constant of 100 N/m and spring B has a spring constant of 200 N/m, and both have the same displacement of 0.20 m

Question

g 12. Spring A has a spring constant of 100 N/m and spring B has a spring constant of 200 N/m, and both have the same displacement of 0.20 m. The spring potential energy of spring A is _____ that of spring B. twice half the same as None of the above

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Hưng Khoa 4 years 2021-08-22T18:01:38+00:00 1 Answers 18 views 0

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  1. thanhcong
    0
    2021-08-22T18:02:41+00:00
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    Answer:

    A. twice

    Explanation:

    Spring potential Energy is expressed as E = 1/2 ke²

    k = spring constant

    e = displacement of the string

    If  Spring A has a spring constant of 100 N/m and displacement of 0.2m, the spring potential energy will be;

    = 1/2 * 100 * 0.2²

    = 50 * 0.04

    = 2Joules

    If spring B has a spring constant of 200 N/m and displacement of 20m, the spring potential energy will be;

    = 1/2 * 200 * 0.2²

    = 100 * 0.04

    = 4Joules

    From the values gotten, it can be seen that the spring potential energy of spring B is twice that of A

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