g 12. Spring A has a spring constant of 100 N/m and spring B has a spring constant of 200 N/m, and both have the same displacement of 0.20 m. The spring potential energy of spring A is _____ that of spring B. twice half the same as None of the above
Question
Answer:
A. twice
Explanation:
Spring potential Energy is expressed as E = 1/2 ke²
k = spring constant
e = displacement of the string
If Spring A has a spring constant of 100 N/m and displacement of 0.2m, the spring potential energy will be;
= 1/2 * 100 * 0.2²
= 50 * 0.04
= 2Joules
If spring B has a spring constant of 200 N/m and displacement of 20m, the spring potential energy will be;
= 1/2 * 200 * 0.2²
= 100 * 0.04
= 4Joules
From the values gotten, it can be seen that the spring potential energy of spring B is twice that of A