Find the intersection point between the lines of equations: 2x-y+6=0 and 2x+3y-6=0 August 2, 2021 by Bơ Find the intersection point between the lines of equations: 2x-y+6=0 and 2x+3y-6=0

Step-by-step explanation: The two equation will intersect each other at the point which will be the solution of the given two equations , and the given equations are , [tex]\implies 2x -y +6=0\\\\\implies 2x + 3y -6=0[/tex] On subtracting the given equations we have, [tex]\implies -y – 3y +6 -(-6) = 0 \\\\\implies -4y = -12 \\\\\implies y = -12/-4\\\\\implies y = 3 [/tex] Put this value in any equation , we have , [tex]\implies 2x -3 +6 =0\\\\\implies 2x = -3 \\\\\implies x =\dfrac{-3}{2} \\\\\implies x =-1.5 [/tex] Hence the lines will Intersect at , [tex]\implies\underline{\underline{ Point=(-1.5, 3)}}[/tex] Reply

for the first one x = 1/2 y-3″ and y = 2 x + 6 and for the other one is x = − 3 /2 y+ 3 and y= − 2 /3 x + 2 how i did this Step 1: Add -3y to both sides. Step 2: Add 6 to both sides. Step 3: Divide both sides by 2. Reply

Step-by-step explanation:The two equation will intersect each other at the point which will be the solution of the given two equations , and the given equations are ,

[tex]\implies 2x -y +6=0\\\\\implies 2x + 3y -6=0[/tex]

On subtracting the given equations we have,

[tex]\implies -y – 3y +6 -(-6) = 0 \\\\\implies -4y = -12 \\\\\implies y = -12/-4\\\\\implies y = 3 [/tex]

Put this value in any equation , we have ,

[tex]\implies 2x -3 +6 =0\\\\\implies 2x = -3 \\\\\implies x =\dfrac{-3}{2} \\\\\implies x =-1.5 [/tex]

Hence the lines will Intersect at ,

[tex]\implies\underline{\underline{ Point=(-1.5, 3)}}[/tex]

for the first one x = 1/2 y-3″ and y

=

2

x

+

6 and for the other one is x

= −

3

/2 y+

3 and y=

−

2

/3 x

+

2

how i did this Step 1: Add -3y to both sides.

Step 2: Add 6 to both sides.

Step 3: Divide both sides by 2.