Find the buoyant force on a brass block 10.5 cm long by 12.3 cm wide by 15.0 cm high when placed in (a) water, (b) glycerine, and (c) mercur

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Find the buoyant force on a brass block 10.5 cm long by 12.3 cm wide by 15.0 cm high when placed in (a) water, (b) glycerine, and (c) mercury

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MichaelMet 5 years 2021-08-19T18:18:07+00:00 1 Answers 32 views 0

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  1. thanhcong
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    2021-08-19T18:19:53+00:00
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    Answer:

    (a) F = 18.99 N

    (b) F = 23.96 N

    (c) F = 258.56 N

    Explanation:

    First we need to find the volume of the block:

    Volume of Block = V = (Length)(Width)(Height)

    V = (10.5 cm)(12.3 cm)(15 cm)

    V = (0.105 m)(0.123 m)(0.15 m)

    V = 0.00194 m³

    Now, the buoyant force i given by the formula:

    F = (Density of Fluid)(V)(g)

    (a)

    F = (Density of Water)(V)(g)

    F = (1000 kg/m³)(0.00194 m³)(9.8 m/s²)

    F = 18.99 N

    (b)

    F = (Density of Glycerine)(V)(g)

    F = (1260 kg/m³)(0.00194 m³)(9.8 m/s²)

    F = 23.96 N

    (c)

    F = (Density of Mercury)(V)(g)

    F = (13600 kg/m³)(0.00194 m³)(9.8 m/s²)

    F = 258.56 N

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